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JEE Main 8 Apr 2024 Shift 2 Solved Paper
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© examsnet.com
Question : 60
Total: 90
A circular table is rotating with an angular velocity of
ω
rad
∕
s
about its axis (see figure). There is a smooth groove along a radial direction on the table. A steel ball is gently placed at a distance of
1
m
on the groove. All the surface are smooth. If the radius of the table is
3
m
, the radial velocity of the ball w.r.t. the table at the time ball leaves the table is
x
√
2
ω
m
∕
s
, where the value of
x
is...........
[8 Apr 2024 Shift 2]
Your Answer:
Validate
Solution:
👈: Video Solution
a
c
=
ω
2
x
v
d
v
d
x
=
ω
2
x
v
∫
0
v
d
v
=
3
∫
1
ω
2
x
dx
v
2
2
=
ω
2
[
x
2
2
]
v
2
2
=
ω
2
2
[
3
2
−
1
2
]
v
=
2
√
2
ω
x
=
2
© examsnet.com
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