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JEE Main 8 April 2017 Solved Paper Solved Paper
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© examsnet.com
Question : 3
Total: 90
Two particles A and B of equal mass M are moving with the same speed v as shown in the figure. They collide completely in elastically and move as a single particle C. The angle θ that the path of C makes with the X-axis is given by :
tan
θ
=
√
3
+
√
2
1
−
√
2
tan
θ
=
√
3
−
√
2
1
−
√
2
tan
θ
=
1
−
√
2
√
2
(
1
+
√
3
)
tan
θ
=
1
−
√
3
1
+
√
2
Validate
Solution:
Using conservation of linear moments,
Along X-axis,
2
M
V
′
cos
θ
=
M
V
sin
30
∘
−
M
V
sin
45
∘
.
.
.
.
.
.
(1)
Along Y-axis,
2
M
v
′
sin
θ
=
M
v
cos
30
∘
+
M
v
cos
45
∘
.
.
.
.
.
.
(2)
Dividing (2) by (1),we get,
sin
θ
cos
θ
=
cos
30
4
+
cos
45
∘
sin
30
∘
−
sin
45
∘
=
√
3
2
+
1
√
2
1
2
−
1
√
2
∴
tan
θ
=
√
3
+
√
2
1
−
√
2
© examsnet.com
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