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JEE Main 9 Apr 2024 Shift 1 Solved Paper
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© examsnet.com
Question : 28
Total: 90
Let the centre of a circle, passing through the point
(
0
,
0
)
,
(
1
,
0
)
and touching the circle
x
2
+
y
2
=
9
, be (h, k). Then for all possible values of the coordinates of the centre
(
h
,
k
)
,
4
(
h
2
+
k
2
)
is equal to _______.
[9 Apr 2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
(
x
−
h
)
2
+
(
y
−
k
)
2
=
h
2
+
k
2
x
2
+
y
2
−
2
hx
−
2
ky
=
0
∵
passes through
(
1
,
0
)
⇒
1
+
0
−
2
h
=
0
⇒
h
=
1
∕
2
∵
OC
=
OP
2
√
(
1
2
)
2
+
k
2
=
3
2
1
4
+
k
2
=
9
4
k
2
=
2
k
=
±
√
2
∴
Possible coordinate of
c
(
h
,
k
)
(
1
2
,
√
2
)
(
1
2
,
−
√
2
)
4
(
h
2
+
k
2
)
=
4
(
1
4
+
2
)
=
4
(
9
4
)
=
9
© examsnet.com
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