Test Index

JEE Main 9 Jan 2019 Shift 1 Solved Paper

© examsnet.com

Question : 14

Total: 90

Two masses m and

are connected at the two ends of a massless rigid rod of length l. The rod is suspended by a thin wire of torsional constant k at the centre of mass of the rod-mass system(see figure). Because of torsional constant k, the restoring torque is τ=kθ for angular displacement θ. If the rod is rotated by θ0 and released, the tension in it when it passes through it mean position will be:

[9-Jan-2019 Shift 1]

3kθ02
l
kθ02
2l
2kθ02
l
kθ02
l

Go to Question:

Prev Question

Next Question

Similar Free Exams: