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JEE Main Chemistry Class 12 Analytical Chemistry Questions
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© examsnet.com
Question : 36
Total: 106
When
10
mL
of an aqueous solution of
KMnO
4
was titrated in acidic medium, equal volume of
0.1
M
of an aqueous solution of ferrous sulphate was required for complete discharge of colour.
The strength of
KMnO
4
in
g
∕
L
is
.
.
.
.
.
.
.
.
×
10
−
2
. (Nearest integer)
[Atomic mass of
K
=
39
,
Mn
=
55
,
O
=
16
]
[27 Aug 2021 Shift 1]
Your Answer:
Validate
Solution:
Let molarity of
KMnO
4
=
x
KMnO
4
n
=
5
+
FeSO
4
n
=
1
→
Fe
(
SO
4
)
3
+
Mn
2
+
(Equivalent of
KMnO
4
reacted) = (Equivalent of
FeSO
4
reacted)
5
x
×
10
=
1
×
0.1
×
10
x = 0.02 M
Molar mass of
KMnO
4
=
158
g
∕
mol
Strength
=
x
×
158
=
0.02
×
158
=
3.16
g
∕
L
∴ x ≈ 316.
© examsnet.com
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