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JEE Main Chemistry Class 11 Chemical Bonding and Molecular Structure Part 1 Questions
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© examsnet.com
Question : 3
Total: 100
The difference between bond orders of
C
O
and
N
O
⊕
is
x
2
where
x
=
_______.
(Round off to the Nearest Integer)
[27 Jul 2021 Shift 1]
Your Answer:
Validate
Solution:
Bond order of
CO
=
3
σ
1
s
2
σ
*
1
s
2
σ
2
s
2
σ
*
2
s
2
σ
2
p
z
2
π
2
p
x
2
π
2
p
y
2
B. O.
=
10
−
4
2
=
3
NO
+
:
B. O.
=
8
−
2
2
=
3
Difference
=
3
−
3
=
0
© examsnet.com
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