(b) Among the given bases (A) and (B), t -butoxide being bulky base favours elimination reaction and ethoxide favours substitution reaction. ∴ when Z∘=CH3CH2O−, (substitution reaction favoured) and when Z=CH3−
CH3
|
C
|
CH3
−O−, (elimination reaction favoured) Hence, µA>µB and ke(B)>ke(A)