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JEE Main Chemistry Class 11 Chemical Kinetics Part 1 Questions
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© examsnet.com
Question : 47
Total: 100
N
2
O
5
decomposes to
N
O
2
and
O
2
and follows first order kinetics. After 50 minutes, the pressure inside the vessel increases from
50
m
m
H
g
to
87.5
m
m
H
g
. The pressure of the gaseous mixture after 100 minutes at constant temperature will be ______.
[Online April 15, 2018 (I)]
136.25
m
m
H
g
106.25
m
m
H
g
175.0
m
m
H
g
116.25
m
m
H
g
Validate
Solution:
Total pressure at 50 minutes
=
50
−
p
1
+
2
p
1
+
p
1
2
=
87.5
50
+
3
p
1
2
=
87.5
3
p
1
2
=
37.5
∴
p
1
=
37.5
×
2
3
=
25
At,
t
=
100
m
i
n
50
−
p
2
2
p
2
p
2
2
50 minutesis half life period
For 100 minutes i.e. for 2 half lives
50
−
p
2
=
12.5
∴
p
2
=
37.5
m
m
of
H
g
Total pressure at 100 minutes
=
50
−
p
2
+
2
p
2
+
p
2
2
=
50
+
3
p
2
2
=
50
+
3
2
×
37.5
=
50
+
56.25
=
106.25
m
m
of
H
g
© examsnet.com
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