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JEE Main Chemistry Class 11 Chemical Kinetics Part 1 Questions
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© examsnet.com
Question : 57
Total: 100
The reaction
2
N
2
O
5
(
g
)
→
4
N
O
2
(
g
)
+
O
2
(
g
)
follows first order kinetics. The pressure of a vessel containing only
N
2
O
5
was found to increase from
50
m
m
H
g
to
87.5
m
m
H
g
in
30
m
i
n
. The pressureexerted by the gases after
60
m
i
n
. will be (assume temperature remains constant):
[Online April 10,2015]
106.25
m
m
H
g
150
m
m
H
g
125
m
m
H
g
116.25
m
m
H
g
Validate
Solution:
2
N
2
O
5
(
g
)
→
4
N
O
2
(
g
)
+
O
2
(
g
)
t
=
0
50 0 0
t
=
30
50
−
2
x
4
x
x
⇒
87.5
=
50
+
3
x
⇒
3
x
=
37.5
⇒
x
=
12.5
⇒
P
N
2
O
5
after 30 mins
=
50
−
25
=
25
⇒
t
1
2
=
30
min
Hence after 60 min, (two half lives),
P
N
2
O
5
remaining
=
50
4
=
12.5
torr
⇒ Hence decrease in
P
N
2
O
5
=
50
−
12.5
=
37.5
torr
⇒
P
N
O
2
=
2
×
37.5
=
75
torr
P
O
2
=
37.5
2
=
18.75
torr
⇒
P
total
=
12.5
+
75
+
18.75
=
106.25
torr
© examsnet.com
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