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JEE Main Chemistry Class 11 Chemical Kinetics Part 2 Questions
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© examsnet.com
Question : 12
Total: 79
The half-life of radioisotopic bromine - 82 is 36 hours. The fraction which remains after one day is
_____
×
10
−
2
.
(
Given antilog
0.2006
=
1.587
)
[29-Jan-2024 Shift 2]
Your Answer:
Validate
Solution:
Half life of bromine
−
82
=
36
hours
t
1
∕
2
=
0.693
K
K
=
0.693
36
=
0.01925
hr
−
1
1
st
order rxn kinetic equation
t
=
2.303
K
log
a
a
−
x
log
a
a
−
x
=
t
×
K
2.303
(
t
=
1
day
=
24
hr
)
log
a
a
−
x
=
24
hr
×
0.01925
hr
−
1
2.303
log
a
a
−
x
=
0.2006
a
a
−
x
=
anti
log
(
0.2006
)
a
a
−
x
=
1.587
If
a
=
1
1
1
−
x
=
1.587
⇒
1
−
x
=
0.6301
=
Fraction remain
after one day
© examsnet.com
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