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JEE Main Chemistry Class 11 Chemical Kinetics Part 2 Questions
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© examsnet.com
Question : 30
Total: 79
For a reversible reaction
A
⇌
B
, the
∆
H
forward reaction
=
20
kJ
mol
−
1
. The activation energy of the uncatalysed forward reaction is
300
kJ
mol
−
1
. When the reaction is catalysed keeping the reactant concentration same, the rate of the catalyzed forward reaction at
27
∘
C
is found to be same as that of the uncatalysed reaction at
327
∘
C
. The activation energy of the catalyzed backward reaction is _______
KJ
mol
−
1
.
[15-Apr-2023 shift 1]
Your Answer:
Validate
Solution:
E
a
=
300
kJ
mol
−
1
E
a
T
=
E
a
′
T
′
(Since rate of catalyzed and uncatalysed reaction is same)
300
600
=
E
a
,
f
′
300
E
a
,
f
′
=
150
20
=
150
20
=
150
−
E
a
,
b
′
E
a
,
b
′
=
130
© examsnet.com
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