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JEE Main Chemistry Class 11 Chemical Kinetics Part 2 Questions
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© examsnet.com
Question : 32
Total: 79
A student has studied the decomposition of a gas
AB
3
at
25
∘
C
. He obtained the following data.
p
(
mm
Hg
)
50
100
200
400
Relative
1
∕
2
(
s
)
4
2
1
0.5
The order of the reaction is
[24-Jan-2023 Shift 2]
0.5
2
1
0 (zero)
Validate
Solution:
t
1
∕
2
∝
(
P
o
)
1
−
n
(
t
1
∕
2
)
1
(
t
1
∕
2
)
2
=
(
P
0
)
1
1
−
n
(
P
0
2
)
2
1
−
n
⇒
(
4
2
)
=
(
50
100
)
1
−
n
⇒
2
=
(
1
2
)
1
−
n
⇒
2
=
(
2
)
n
−
1
⇒
n
−
1
=
1
⇒
n
=
2
© examsnet.com
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