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JEE Main Chemistry Class 11 Chemical Thermodynamics Part 1 Questions
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© examsnet.com
Question : 49
Total: 100
A gas undergoes change from state
A
to state
B
. In this process, the heat absorbed and work done by the gas is 5
J
and
8
J
, respectively. Now gas is brought back to
A
by another process during which
3
J
of heat is evolved. In this reverse process of
B
to
A
:
[Online April 9,2017]
10
J
of the work will be done by the gas.
6
J
of the work will be done by the gas.
10
J
of the work will be done by the surrounding on gas.
6
J
of the work will be done by the surrounding on gas.
Validate
Solution:
∆
U
A
B
=
q
+
w
=
+
5
+
(
−
8
)
=
−
3
q
=
−
3
,
∆
U
B
A
=
+
3
∆
U
B
A
=
q
+
w
⇒
3
=
−
3
+
w
⇒
w
=
+
6
(work done on the system).
© examsnet.com
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