+HCl(aq)⟶FeCl2(aq)+H2(g) ( Moles of Fe= Moles of H2) moles =
50
55.85
0.8952mol0.8952mol =0.8952mol Work done can be given by W=−pext ∆V W=−∆ngRT where, ∆ng={ gaseous moles on product side } - {gaseous mole on reactant side} =0.8952−0 W=−0.8952×8.314×298 =−2217.92J Closest integer =2218