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JEE Main Chemistry Class 11 Chemical Thermodynamics Part 2 Questions
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© examsnet.com
Question : 7
Total: 88
Consider the two different first order reactions given below
A
+
B
⟶
C
(Reaction 1
)
P
⟶
Q
(Reaction 2)
The ratio of the half life of Reaction 1 : Reaction 2 is
5
:
2
. If
t
1
and
t
2
represent the time taken to complete
2
∕
3
rd
and
4
∕
5
of Reaction 1 and Reaction 2, respectively, then the value of the ratio
t
1
:
t
2
is
×
10
−
1
(nearest integer).
[Given:
log
10
(
3
)
=
0.477
and
log
10
(
5
)
=
0.699
]
[6 Apr 2024 Shift 2]
Your Answer:
Validate
Solution:
(
t
1
∕
2
)
I
(
t
1
∕
2
)
II
=
K
2
K
1
=
5
2
∴
K
1
t
1
=
ln
1
1
−
2
3
=
ln
3
K
2
t
2
=
ln
1
1
−
4
5
=
ln
5
⇒
K
1
K
2
×
t
1
t
2
=
0.477
0.699
⇒
t
1
t
2
=
0.477
0.699
×
5
2
=
1.7
=
17
×
10
−
1
© examsnet.com
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