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JEE Main Chemistry Class 11 Classification of Elements and Periodicity in Properties 1 Questions

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Question : 97

Total: 100

The formation of the oxide ion 02−(g) requires first an exothermic and then an endothermic step as shown below
O(g)+e−=O−(g)∆H0=−142kJmol−1

O−(g)+e−=O2−(g)∆H0=844kJmol−1
This is because

O - ion will tend toresist the addition of another electron
Oxygen has high electron affinity
Oxygen is more elecronegative
O -ion has comparativelylarger size than oxygen atom

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