Solution:
[Cr(H2O)6]2+⇒Cr2+⇒3d4⇒t2g1,1,1,eg1,0
No. of unpaired e : 4
[Fe(H2O)6]2+⇒Fe2+⇒3d6⇒t2g2,1,1,eg1,1
No. of unpaired e : 4
[Fe(NH3)6]2+⇒Fe2+⇒3d6⇒t2g2,1,1,eg1,1
No. of unpaired e : 4
[Co(OH)4]2−⇒Co2+⇒3d⊤⇒e2,2,t21,1,1
No. of unpaired e : 3
[CoCl4]2−⇒Co2+⇒3d7⇒e2,2,t21,1,1
No. of unpaired e:3
[Mn(H2O)6]2+⇒Mn2+⇒3d5⇒t2g1,1,1,eg1,1
No. of unpaired e:5
So [Cr(H2O)6]2+ and [Fe(H2O)6]2+ have same magnetic moment (spin only).
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