The reaction involved in the process is given below PbSO4→Pb2++SO42− Pb2++H2O→PbO2+4H++2e− So, half cell reaction is PbSO4→Pb4++2e− According tothe reaction: PbSO4→Pb4++2e− We require 2F for the electrolysis of 1mol or 303g of PbSO4 ∴ Amount of PbSO4 electrolysed by 0.05F =