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JEE Main Chemistry Class 11 Electrochemistry Part 1 Questions
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© examsnet.com
Question : 9
Total: 100
Assume a cell with the following reaction
C
u
(
s
)
+
2
A
g
+
(
1
×
10
−
3
M
)
→
C
u
2
+
(
0.250
M
)
+
2
A
g
(
s
)
E
cell
⊝
=
2.97
V
E
cell
for the above reaction is __________ V.
(Nearest integer)
[
Given :
log
2.5
=
0.3979
,
T
=
298
K
]
[22 Jul 2021 Shift 2]
Your Answer:
Validate
Solution:
E
=
E
°
−
0.059
2
log
[
C
u
+
2
]
[
A
g
+
]
2
=
2.97
−
0.059
2
log
0.25
(
10
−
3
)
2
=
2.81
V
© examsnet.com
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