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JEE Main Chemistry Class 11 Electrochemistry Part 2 Questions
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© examsnet.com
Question : 44
Total: 79
The standard electrode potential
(
M
3
+
∕
M
2
+
)
for
V
,
Cr
,
Mn
&
Co
are
−
0.26
V
,
−
0.41
V
,
+
1.57
V
and
+
1.97
V
, respectively. The metal ions which can liberate
H
2
from a dilute acid are
[29-Jan-2023 Shift 1]
V
2
+
and
Mn
2
+
Cr
2
+
and
CO
2
+
V
2
+
and
Cr
2
+
Mn
2
+
and
Co
2
+
Official Ans. by NTA (3)
Validate
Solution:
Metal cation with
(
−
)
value of reduction potential
(
M
+
3
∕
M
+
2
)
or with
(
+
)
value of oxidation potential
(
M
+
2
∕
M
+
3
)
will liberate
H
2
Therefore they will reduce
H
+
i.eV
eV
+
2
and
Cr
+
2
© examsnet.com
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