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JEE Main Chemistry Class 11 Equilibrium Questions Part 1 Questions
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© examsnet.com
Question : 16
Total: 100
Following four solutions are prepared by mixing different volumes of
N
a
O
H
and
H
C
l
of different concentrations,
p
H
of which one of them will be equal to 1 ?
[Online April 15, 2018 (II)]
55
m
L
M
10
H
C
l
+
45
m
L
M
10
N
a
O
H
75
m
L
M
5
H
C
l
+
25
m
L
M
5
N
a
O
H
100
m
L
M
10
H
C
l
+
100
m
L
M
10
N
a
O
H
60
m
L
M
10
H
C
l
+
40
m
L
M
10
N
a
O
H
Validate
Solution:
75
m
L
M
5
H
C
l
+
25
m
L
M
5
N
a
O
H
25
m
L
M
5
N
a
O
H
will neutralise
25
m
L
M
5
H
C
l
75
−
25
=
50
m
L
M
5
H
C
l
will remain.
Total volume will be
75
+
25
=
100
m
L
50
m
L
M
5
H
C
l
is diluted to
100
m
L
[
H
+
]
=
[
H
C
l
]
=
M
5
×
50
100
=
M
10
p
H
=
−
log
10
[
H
+
]
=
−
log
10
M
10
=
1
© examsnet.com
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