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JEE Main Chemistry Class 11 Equilibrium Questions Part 1 Questions
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© examsnet.com
Question : 2
Total: 100
For the equilibrium
2
H
2
O
⇌
H
3
O
+
+
O
H
−
;
the value of
∆
G
∘
at
298
K
is approximately:
[Jan. 11, 2019 (II)]
100
k
J
m
o
l
−
1
−
80
k
J
m
o
l
−
1
80
k
J
m
o
l
−
1
−
100
k
J
m
o
l
−
1
Validate
Solution:
∆
G
=
∆
G
∘
+
R
T
ln
Q
At equilibrium;
∆
G
=
0
and
Q
=
K
e
q
⇒
∆
G
∘
=
−
2.303
R
T
log
K
w
=
−
2.303
×
8.314
×
298
×
log
10
−
14
=
79.9
k
J
∕
m
o
l
≈
80
k
J
∕
m
o
l
© examsnet.com
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