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JEE Main Chemistry Class 11 Equilibrium Questions Part 2 Questions
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© examsnet.com
Question : 26
Total: 100
K
a
for butyric acid
(
C
3
H
7
COOH
)
is
2
×
10
−
5
. The
pH
of
0.2
M
solution of butyric acid is _______
×
10
−
1
. (Nearest integer)
[Given
log
2
=
0.30
]
[28-Jul-2022-Shift-1]
Your Answer:
Validate
Solution:
K
a
of Butyric acid
⇒
2
×
10
−
5
PKa
=
4.7
pH
of
0.2
M
solution
pH
=
1
2
pK
a
−
1
2
log
C
=
1
2
(
4
⋅
7
)
1
2
log
(
0.2
)
=
2.35
+
0.35
=
2.7
pH
=
27
×
10
−
1
© examsnet.com
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