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JEE Main Chemistry Class 11 Equilibrium Questions Part 2 Questions
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© examsnet.com
Question : 45
Total: 100
A solution is
0.1
M
in
C
l
−
and
0.001
M
in
C
r
O
4
2
−
.
Solid
A
g
N
O
3
is gradually added to it Assuming that the addition does not change in volume and
K
sp
(
A
g
C
l
)
=
1.7
×
10
−
10
M
2
and
K
s
p
(
A
g
2
C
r
O
4
)
=
1.9
×
10
−
12
M
3
Select correct statement from the following:
[20 Jul 2021 Shift 2]
A
g
C
l
precipitates first because its
K
s
p
is high.
A
g
2
C
r
O
4
precipitates first as its
K
s
p
is low.
A
g
2
C
r
O
4
precipitates first because the amount of
A
g
+
needed is low.
AgCl will precipitate first as the amount of
A
g
+
needed to precipitate is low.
Validate
Solution:
(i)
[
A
g
+
]
required to ppt
A
g
C
l
(
s
)
K
s
p
=
I
P
=
[
A
g
+
]
[
C
l
−
]
=
1.7
×
10
−
10
[
A
g
+
]
=
1.7
×
10
−
9
(ii)
[
A
g
+
]
required to ppt
A
g
2
C
r
O
4
(
s
)
K
s
p
=
I
P
=
[
A
g
+
]
2
[
C
r
O
4
−
2
]
=
1.9
×
10
−
12
[
A
g
+
]
=
4.3
×
10
−
5
[
A
g
+
]
required to ppt
A
g
C
l
is low so
A
g
C
l
will
p
p
t
1
s
t
© examsnet.com
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