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JEE Main Chemistry Class 11 Organic Chemistry Some Basic Principles and Techniques 1 Questions
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© examsnet.com
Question : 10
Total: 100
In an estimation of bromine by Carius method,
1.6
g
of an organic compound gave
1.88
g
of
A
g
B
r
. The mass percentage of bromine in the compound is
(Atomic mass,
A
g
=
108
,
B
r
=
80
g
m
o
l
−
1
)
[NV, Sep. 06, 2020 (I)]
Your Answer:
Validate
Solution:
Mass of organic compound
=
1.6
g
Mass of
A
g
B
r
=
1.88
g
Moles of
B
r
=
Moles of
A
g
B
r
=
1.88
188
=
0.01
Mass of
B
r
=
0.01
×
80
=
0.80
g
%
of
B
r
=
0.80
×
100
1.60
=
50
%
Alternate Method:
%
of Br
=
Wt. of
A
g
B
r
W
t
. of
O
.
C
.
×
Molar mass of
B
r
A
g
B
r
×
100
=
1.88
1.6
×
80
188
×
100
=
50
%
© examsnet.com
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