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JEE Main Chemistry Class 11 Redox Reactions Questions
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© examsnet.com
Question : 62
Total: 79
Given:
C
o
3
+
+
e
−
→
C
o
2
+
;
E
∘
=
+
1.81
V
P
b
4
+
+
2
e
−
→
P
b
2
+
;
E
0
=
+
1.67
V
C
e
4
+
+
e
−
→
C
e
3
+
;
E
o
=
+
1.61
V
B
i
3
+
+
3
e
−
→
B
i
;
E
o
=
+
0.20
V
oxidizing power of thespecies will increase in the order:
[April 12, 2019(I)]
C
e
4
+
<
P
b
4
+
<
B
i
3
+
<
C
o
3
+
B
i
3
+
<
C
e
4
+
<
P
b
4
+
<
C
o
3
+
C
o
3
+
<
C
e
4
+
<
B
i
3
+
<
P
b
4
+
C
o
3
+
<
P
b
4
+
<
C
e
4
+
<
B
i
3
+
Validate
Solution:
Higher the reduction potential, higher will be oxidising power. So,
B
i
3
+
<
C
e
4
+
<
P
b
4
+
<
C
o
3
+
© examsnet.com
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