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JEE Main Chemistry Class 11 Solutions Part 1 Questions

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Question : 34

Total: 100

The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in molkg−1 ) of the aqueous solution is :

[April 12, 2019 (I)]

13.88×10−2
13.88×10−1
13.88
13.88×10−3

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