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JEE Main Chemistry Class 11 Solutions Part 1 Questions
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© examsnet.com
Question : 81
Total: 100
Two liquids
X
and
Y
form an ideal solution. At
300
K
, vapour pressure of the solution containing
1
m
o
l
of
X
and
3
m
o
l
of
Y
is
550
m
m
H
g
. At the same temperature, if 1 mol of
Y
is further added to this solution, vapour pressure of the solution increases by
10
m
m
H
g
. Vapour pressure (in
m
m
H
g
) of
X
and
Y
in their pure states will be, respectively:
[2009]
300 and 400
400 and 600
500 and 600
200 and 300
Validate
Solution:
P
total
=
P
x
∘
X
x
+
P
y
∘
X
y
550
=
P
x
∘
×
1
4
+
P
y
∘
×
3
4
P
x
∘
+
3
P
y
∘
=
550
×
4
. . . (i)
In second case,
P
total
=
P
x
∘
×
1
5
+
P
y
∘
×
4
5
P
x
∘
+
4
P
y
∘
=
560
∘
5
. . . (ii)
Subtract (i) from (ii)
∴
P
y
∘
=
560
×
5
−
550
×
4
=
600
∵
P
x
∘
=
400
© examsnet.com
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