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JEE Main Chemistry Class 11 Solutions Part 2 Questions

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Question : 2

Total: 80

2.5g of a non-volatile, non-electrolyte is dissolved in 100g of water at 25∘C. The solution showed a boiling point elevation by 2∘C. Assuming the solute concentration in negligible with respect to the solvent concentration, the vapour pressure of the resulting aqueous solution is ______ mm of Hg (nearest integer)
[Given : Molal boiling point elevation constant of water (Kb)=0.52K.kg‌mol−1,
1‌atm pressure =760‌mm of Hg, molar mass of water =18gmol−1]

[4 Apr 2024 Shift 1]

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