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JEE Main Chemistry Class 11 Solutions Part 2 Questions
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© examsnet.com
Question : 34
Total: 80
Sea water contains
29.25
%
NaCl
and
19
%
MgCl
2
by weight of solution. The normal boiling point of the sea water is _______
∘
C
(Nearest integer)
Assume
100
%
ionization for both
NaCl
and
MgCl
2
Given :
K
b
(
H
2
O
)
=
0.52
K
kg
mol
−
1
Molar mass of
NaCl
and
MgCl
2
is 58.5 and
95
g
mol
−
1
respectivley.
[13-Apr-2023 shift 2]
Your Answer:
Validate
Solution:
Amount of solvent
=
100
−
(
29.25
+
19
)
=
51.75
g
∆
T
b
=
[
2
×
29.25
×
1000
58.5
×
51.75
+
3
×
19
×
1000
95
×
51.75
]
×
0.52
∆
T
b
=
16.075
∆
T
b
=
(
T
b
)
solution
−
(
T
b
)
solvent
(
t
)
solution
=
100
+
16.07
=
116.07
∘
C
© examsnet.com
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