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Test Index
JEE Main Chemistry Class 11 Some Basic Concepts of Chemistry Part 1 Questions
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© examsnet.com
Question : 26
Total: 100
A solution of two components containing
n
1
moles of the
1
st
component and
n
2
moles of the
2
nd
component is prepared.
M
1
and
M
2
are the molecular weights of component 1 and 2 respectively. If
d
is the density of the solution in
g
mL
−
1
,
C
2
is the molarity and
x
2
is the mole fraction of the
2
nd
component, then
C
2
can be expressed as:
[Sep. 06,2020(I)]
C
2
=
1000
x
2
M
1
+
x
2
(
M
2
−
M
1
)
C
2
=
d
x
2
M
2
+
x
2
(
M
2
−
M
1
)
C
2
=
1000
d
x
2
M
1
+
x
2
(
M
2
−
M
1
)
C
2
=
d
x
1
M
2
+
x
2
(
M
2
−
M
1
)
Validate
Solution:
1st component
2nd component
mole
n
1
n
2
m.w
M
1
M
2
mass
n
1
M
1
n
2
M
2
[
∵
mass
=
mole
×
m.w.
]
Mass of solution
=
n
1
M
1
+
n
2
M
2
Mole fraction of the
2
nd
component
(
x
2
)
=
n
2
n
1
+
n
2
⇒
n
1
=
n
2
(
1
−
x
2
)
x
2
Mass of solution
=
n
1
M
1
+
n
2
M
2
=
n
2
M
1
(
1
−
x
2
)
x
2
+
n
2
M
2
=
n
2
x
2
[
M
2
x
2
−
x
2
M
1
+
M
1
]
Volume of solution
=
n
2
[
M
2
x
2
−
x
2
M
1
+
M
1
]
1000
d
x
2
C
2
=
1000
n
2
d
x
2
n
2
[
M
2
x
2
−
x
2
M
1
+
M
1
]
⇒
C
2
=
1000
d
x
2
M
1
+
x
2
(
M
2
−
M
1
)
© examsnet.com
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