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JEE Main Chemistry Class 11 Some Basic Concepts of Chemistry Part 1 Questions
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© examsnet.com
Question : 45
Total: 100
The amount of sugar
(
C
12
H
22
O
11
)
required to prepare 2
L
of its
0.1
M
aqueous solution is:
[Jan. 10 2019(II)]
136.8
g
17.1
g
68.4
g
34.2
g
Validate
Solution:
As we know,
Molarity
=
No. of moles of sugar
Volume of solution (in L)
⇒
0.1
=
No. of moles of sugar
2
L
So, no. of moles of sugar
=
0.2
mole
∴ Mass of sugar
=
No. of moles of sugar × Molar mass of sugar
=
0.2
×
342
=
68.4
g
© examsnet.com
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