No. of moles of oxygen in 0.16g of oxygen molecule =
0.16g
32g∕mol
=0.005mol 2NaClO3
∆
→
2NaCl+3O2 According to the reaction, 3 moles of O2=2 moles of NaCl=2 moles of AgCl Molar mass of AgCl=143.5g∕mol 0.005 moles of O2 will ppt. =0.005×
2
3
moles AgCl =0.0033moles of AgCl ∴ Mass of AgCl (in g) obtained will be =143.5g∕mol×0.0033moles=0.48g.