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JEE Main Chemistry Class 11 Some Basic Concepts of Chemistry Part 1 Questions
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© examsnet.com
Question : 99
Total: 100
Number of atoms in
558.5
gram
F
e
(at. wt. of
F
e
=
55.85
g
m
o
l
−
1
)
is
[2002]
twice that in
60
g
carbon
6.023
×
10
22
half that in
8
g
He
558.5
×
6.023
×
10
23
Validate
Solution:
F
e
(
N
o
.
of moles )
=
558.5
55.85
=
10
m
o
l
C (No. of moles) in
60
g
of
C
=
60
∕
12
=
5
m
o
l
.
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