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JEE Main Chemistry Class 11 States of Matter Questions
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© examsnet.com
Question : 12
Total: 77
A
10
g
mixture of hydrogen and helium is contained in a vessel of capacity
0.0125
m
3
at 6 bar and
27
∘
C
. The mass of helium in the mixture is _______ g. (nearest integer)
Given:
R
=
8.3
J
K
−
1
mol
−
1
(Atomic masses of
H
and
He
are
1
u
and
4
u
, respectively)
[26-Jul-2022-Shift-2]
Your Answer:
Validate
Solution:
Number of moles of mixture of
H
2
and
He
=
P
V
R
T
=
6
×
10
5
×
0.0125
8.3
×
300
=
3
Let the mass of He in
10
g
mixture be
xg
∴
x
4
+
10
−
x
2
=
3
On solving
x
=
8
g
∴
Mass of
He
in the mixture
=
8
g
© examsnet.com
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