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JEE Main Chemistry Class 11 States of Matter Questions
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© examsnet.com
Question : 49
Total: 77
At very high pressures, the compressibility factor of one mole of a gas is given by:
[Online April 9, 2016]
1
+
P
b
R
T
P
b
R
T
z
1
−
P
b
R
T
1
−
b
(
V
R
T
)
Validate
Solution:
According to van der Waals equation for one mole of gas
(
P
+
a
V
2
)
(
V
−
b
)
=
R
T
At very high pressure
P
>
>
a
V
2
So,
a
V
2
is negligible.
P
(
V
−
b
)
=
R
T
;
P
V
−
P
b
=
R
T
on dividing
R
T
on both sides.
∴
Z
=
1
+
P
b
R
T
compressibility factor.
© examsnet.com
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