Number of radial nodes =(n−I−1) [ n= principal quantum number, I= az imuthal quantum number] Number of angular nodes =1 (a) 3p(n=3,I=1)⇒11 (b) 4f(n=4,I=3)⇒03 (c) 4d(n=4,I=2)⇒12 (d) 5d(n=5,I=2)⇒22 So, 5d-orbital has two radial as well as two angular nodes (option-d). Note I=0 for s-orbital, I=1 for p-orbital, I=2 for d-orbital and I=3 for f−orbital.