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JEE Main Chemistry Class 12 The P Block Elements (15-18) Part 1 Questions
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© examsnet.com
Question : 21
Total: 100
A xenon compound '
A
' upon partial hydrolysis gives
X
e
O
2
F
2
. The number of lone pair of electrons present in compound
A
is (Round off to the nearest integer).
[18 Mar 2021 Shift 2]
Your Answer:
Validate
Solution:
Xenon hexa fluoride (A) on partial hydrolysis gives
X
e
O
2
F
2
as a product.
X
e
F
6
(
A
)
Xenon hexa fluoride
+
2
H
2
O
Partially
⟶
X
e
O
2
F
2
+
4
H
F
Structure of
X
e
F
6
∴
Total no. of lone pair
=
lone pair on
X
e
+
6
×
lone pair on
F
=
1
+
6
×
3
=
19
© examsnet.com
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