‌2‌NOCl(g)⇌‌2‌NO(g)+Cl2(g) At ‌t=0:   2      0      0 At ‌t=t‌eq ‌:  2−2x    2x      0
Given that at equilibrium, concentration of NO=0.4‌mol∕L ∴2x=0.4 ⇒x=0.2 ∴ Concentration of NOCl at equilibrium, [NOCl]eq=2−2×0.2=1.6 and [NO]eq=0.4 and [Cl2]eq=0.2 We know, KC=‌