Given, Mass of ideal gas =100‌gm Let the molar mass of ideal gas =M ∴ Number of moles of gas (n)=‌
100
M
Volume of cylinder (V)=416L Temperature (T)=(27+273)K=300K Pressure (P)=1.5 bar R=0.083L‌bar‌K−1‌mol−1 Using ideal gas equation, PV=nRT ⇒1.5×416=‌