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JEE Main Math Class 11 Binomial Theorem Part 2 Questions
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© examsnet.com
Question : 17
Total: 115
Number of integral terms in the expansion of
{
7
(
1
2
)
+
11
(
1
6
)
}
824
is equal to
[30-Jan-2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
General term in expansion of
(
(
7
)
1
∕
2
+
(
11
)
1
∕
6
)
824
is
t
r
+
1
=
824
C
r
(
7
)
824
−
r
2
(
11
)
r
∕
6
For integral term,
r
must be multiple of 6 .
Hence
r
=
0
,
6
,
12
,
.
.
.
.
.
.
.
.
.822
© examsnet.com
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