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JEE Main Math Class 11 Coordinate Geometry Part 5 Questions
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© examsnet.com
Question : 27
Total: 100
If the points of intersection of two distinct conics
x
2
+
y
2
=
4
b
and
x
2
16
+
y
2
b
2
=
1
lie on the curve
y
2
=
3
x
2
, then
3
√
3
times the area of the rectangle formed by the intersection points is__
[29-Jan-2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
Putting
y
2
=
3
x
2
in both the conics
We get
x
2
=
b
and
b
16
+
3
b
=
1
⇒
b
=
4
,
12
(
b
=
4
is rejected because curves coincide)
∴
b
=
12
Hence points of intersection are
(
±
√
12
,
±
6
)
⇒
area of rectangle
=
432
© examsnet.com
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