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Test Index
JEE Main Math Class 11 Coordinate Geometry Part 6 Questions
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© examsnet.com
Question : 11
Total: 33
The area (in square units) of the region enclosed by the ellipse
x
2
+
3
y
2
=
18
in the first quadrant below the line
y
=
x
is :
[9 Apr 2024 Shift 2]
√
3
π
+
3
4
√
3
π
√
3
π
−
3
4
√
3
π
+
1
Validate
Solution:
👈: Video Solution
x
2
18
+
y
2
6
=
1
x
2
18
+
3
x
2
18
=
1
⇒
4
x
2
=
18
⇒
x
2
=
9
2
3
√
2
∫
3
√
2
√
18
−
x
2
√
3
dx
=
1
√
3
(
x
√
18
−
x
2
2
+
18
2
s
i
n
−
1
x
3
√
2
)
3
√
2
3
√
2
=
1
√
3
(
9
×
π
2
−
3
2
√
2
×
3
√
3
√
2
−
9
×
π
6
)
Required Area
=
1
2
×
9
2
+
(
18
π
6
−
9
√
3
4
)
1
√
3
=
√
3
π
© examsnet.com
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