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JEE Main Math Class 11 Coordinate Geometry Part 6 Questions
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© examsnet.com
Question : 9
Total: 33
The area of the region in the first quadrant inside the circle
x
2
+
y
2
=
8
and outside the pnrabola
y
2
=
2
x
is equal to :
[8 Apr 2024 Shift 2]
π
2
−
1
3
π
−
2
3
π
2
−
2
3
π
−
1
3
Validate
Solution:
👈: Video Solution
Required area
=
Ar
(
circle from
0
to
2
)
−
ar
(
para from
0
to
2
)
=
2
∫
0
√
8
−
x
2
dx
−
2
∫
0
√
2
x
dx
=
[
x
2
√
8
−
x
2
+
8
2
s
i
n
−
1
x
2
√
2
]
0
2
−
√
2
[
x
√
x
3
∕
2
]
0
2
=
2
2
√
8
−
4
+
8
2
s
i
n
−
1
2
2
√
2
−
2
√
2
3
(
2
√
2
−
0
)
⇒
2
+
4
⋅
π
4
−
8
3
=
π
−
2
3
© examsnet.com
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