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JEE Main Math Class 11 Permutations and Combinations 1 Questions
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© examsnet.com
Question : 97
Total: 100
The sum of integers from 1 to 100 that are divisible by 2 or 5 is
[2002]
3000
3050
3600
3250
Validate
Solution:
Required sum
=
(
2
+
4
+
6
+
.
.
.
+
100
)
+
(
5
+
10
+
15
+
.
.
.
+
100
)
−
(
10
+
20
+
.
.
.
+
100
)
=
2
(
1
+
2
+
3
.
.
.
+
50
)
+
5
(
1
+
2
+
3
+
.
.
.
+
50
)
=
2550
+
1050
−
530
=
3050
.
© examsnet.com
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