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JEE Main Math Class 11 Permutations and Combinations 2 Questions
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© examsnet.com
Question : 11
Total: 87
Let
α
=
(
4
!
)
!
(
4
!
)
3
!
and
β
=
(
5
!
)
!
(
5
!
)
4
!
. Then :
[27-Jan-2024 Shift 2]
α
∈
N
and
β
∉
N
α
∉
N
and
β
∈
N
α
∈
N
and
β
∈
N
α
∉
N
and
β
∉
N
Validate
Solution:
👈: Video Solution
α
=
(
4
!
)
!
(
4
!
)
3
!
,
β
=
(
5
!
)
!
(
5
!
)
4
!
α
=
(
24
)
!
(
4
!
)
6
,
β
=
(
120
)
!
(
5
!
)
24
Let 24 distinct objects are divided into 6 groups of 4 objects in each group.
No. of ways of formation of group
=
24
!
(
4
!
)
6
.6
!
∈
N
Similarly,
Let 120 distinct objects are divided into 24 groups of 5 objects in each group.
No. of ways of formation of groups
=
(
120
)
!
(
5
!
)
24
⋅
24
!
∈
N
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