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JEE Main Math Class 11 Relations and Functions Part 2 Questions
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© examsnet.com
Question : 2
Total: 95
Let the relations
R
1
and
R
2
on the set
X
=
{
1
,
2
,
3
,
.
.
.
,
20
}
be given by
R
1
=
{
(
x
,
y
)
:
2
x
−
3
y
=
2
}
and
R
2
=
{
(
x
,
y
)
:
−
5
x
+
4
y
=
0
}
. If
M
and
N
be the minimum number of elements required to be added in
R
1
and
R
2
, respectively, in order to make the relations symmetric, then
M
+
N
equals
[6 Apr 2024 Shift 1]
8
16
12
10
Validate
Solution:
👈: Video Solution
x
=
{
1
,
2
,
3
,
.
.
.
.
.
.
.20
}
R
1
=
{
(
x
,
y
)
:
2
x
−
3
y
=
2
}
R
2
=
{
(
x
,
y
)
:
−
5
x
+
4
y
=
0
}
R
1
=
{
(
4
,
2
)
,
(
7
,
4
)
,
(
10
,
6
)
,
(
13
,
8
)
,
(
16
,
10
)
,
(
19
,
12
)
}
R
2
=
{
(
4
,
5
)
,
(
8
,
10
)
,
(
12
,
15
)
,
(
16
,
20
)
}
in
R
1
6
element needed
in
R
2
4
element needed
So, total
6
+
4
=
10
elemen
© examsnet.com
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