a1,a2,a3,...,a10 arein APcommon difference =−3 b1,b2,b3,...,b10 arein GPcommon ratio =2 Since,c =ak+bk,k=1,2,3......,10 ∴c2=a2+b2=12 c3=a3+b3=13 Now, c3−c2=1 ⇒(a3−a2)+(b3−b2)≠1 ⇒−3+(2b2−b2)≠1 ⇒b2=4 ∴a2=8 So, AP is 11,8,5,.... and GP is 2,4,8,.... Now,