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JEE Main Math Class 11 Straight Lines and Pair of Straight Lines 1 Questions
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© examsnet.com
Question : 13
Total: 100
The locus of the mid-points of the perpendiculars drawn from points on the line,
x
=
2
y
to the line
x
=
y
is:
[Jan. 7, 2020 (II)]
2
x
−
3
y
=
0
5
x
−
7
y
=
0
3
x
−
2
y
=
0
7
x
−
5
y
=
0
Validate
Solution:
Since, slope of
P
Q
=
k
−
α
h
−
2
α
=
−
1
⇒
k
−
α
=
−
h
+
2
α
⇒
α
=
h
+
k
3
Also,
2
h
=
2
α
+
β
and
2
k
=
α
+
β
⇒
2
h
=
α
+
2
k
⇒
α
=
2
h
−
2
k
From (i) and (ii), we have
h
+
k
3
=
2
(
h
−
k
)
So, locus is
6
x
−
6
y
=
x
+
y
⇒
5
x
=
7
y
⇒
5
x
−
7
y
=
0
© examsnet.com
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