Given lines are 4ax+2ay+c=0 5bx+2by+d=0 The point of intersection will be
x
2ad−2bc
=
−y
4ad−5bc
=
1
8ab−10ab
⇒x=
2(ad−bc)
−2ab
=
bc−ad
ab
⇒y=
5bc−4ad
−2ab
=
4ad−5bc
2ab
∵ Point of intersection is in fourth quadrant so x is positive and y is negative. Also distance from axes is same So x=−y (∵ distance from x -axis is −y as y is negative)